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-.5x^2-5x+1600=0
We add all the numbers together, and all the variables
-0.5x^2-5x+1600=0
a = -0.5; b = -5; c = +1600;
Δ = b2-4ac
Δ = -52-4·(-0.5)·1600
Δ = 3225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3225}=\sqrt{25*129}=\sqrt{25}*\sqrt{129}=5\sqrt{129}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5\sqrt{129}}{2*-0.5}=\frac{5-5\sqrt{129}}{-1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5\sqrt{129}}{2*-0.5}=\frac{5+5\sqrt{129}}{-1} $
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